Q.

If the curves y=x3-3x2-8x-4 and y=3x2+7x+4 touch each at a point P then the equation of common tangent at P is

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a

2x-y+1=0

b

x+y+1=0

c

2x+y+1=0

d

x-y+1=0

answer is A.

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Detailed Solution

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Solving the given curves will get P=-1, 0,

  dydxP=6-1+7=1 Equation of tangent is  y-0=1x+1 x-y+1=0

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If the curves y=x3-3x2-8x-4 and y=3x2+7x+4 touch each at a point P then the equation of common tangent at P is