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If the de-Broglie wavelengths for a proton and for a $α -$ particle are equal, then the ratio of their velocities will be

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4 : 1

2 : 1

1 : 2

1 : 4

answer is A.

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Detailed Solution

$λ = \frac{h}{m_{1} v_{1}} = \frac{h}{m_{2} v_{2}}; ∴ \frac{v_{1}}{v_{2}} = \frac{m_{2}}{m_{1}} = \frac{4}{1}$

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