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If the density of a substance is $7100 k g m^{- 3}$ , what is its relative density?

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7100

7.1

$71 \times 10^{5}$

answer is C.

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Detailed Solution

Given:

The density of the substance: $7100 k g / m^{3}$

The density of water at $4^{o} C$ = $1000 k g / m^{3}$

$R e l a t i v e d e n s i t y = \frac{D e n s i t y o f s u b s t a n c e}{D e n s i t y o f w a t e r a t 4^{o} C}$

$R e l a t i v e d e n s i t y = \frac{7100}{1000}$

$R e l a t i v e d e n s i t y = 7.1$

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