If the density of gold is 19300 kg/m³ then find the specific gravity of gold.

Specific gravity which is also called relative density is the ratio of the density of an object to the density of water at 4 degrees Celsius at standard atmospheric pressure.

Specific gravity = $\frac{\mathrm{Density} \mathrm{of} \mathrm{the} \mathrm{substance} }{\mathrm{Density} \mathrm{of} \mathrm{water} }$

The density of water is 1000 kg/m³; the density of gold is 19300 kg/m³.
$\Rightarrow$Specific gravity = $\frac{19300}{1000 }$= 19.3

Therefore, the specific gravity of gold will be 19.3.