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Q.

If the dielectric constant of substance is $K = \frac{4}{3},$ then its electric susceptibility is $(ε_{0} -$ permittivity of free space)

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a

$3 ε_{0}$

b

$\frac{4}{3} ε_{0}$

c

$\frac{3}{4} ε_{0}$

d

$\frac{ε_{0}}{3}$

answer is A.

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Detailed Solution

$Ψ_{0} = ε_{0} (K - 1)$

$Ψ_{0} = \frac{1}{3} ε_{0}$

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If the dielectric constant of substance is K=43, then its electric susceptibility is (ε0−permittivity of free space)