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Q.

If the difference between the roots of the equation $x^{2} + p x + 8 = 0$ is 2, then the value of $p$ is

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a

$+ 6$

b

$+ 4$

c

$- 6$

d

$- 4$

answer is A, C.

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Detailed Solution

Quadratic equations $x^{2} + p x + 8 = 0$

$α, β$ are roots

$α - β = 2, α + β = - p, α β = 8$

$\sqrt{{(α + β)}^{2} - 4 α β} = 2$

$\sqrt{p^{2} - 32} = 2$

$p^{2} - 32 = 4$

$p^{2} = 36$

$p = \pm 6$

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