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If the discriminant of quadratic equation $b^{2} - 4 ac = 0$ , then the roots are

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Real and equal

Roots are equal

No real roots

Roots are unequal and irrational

answer is A.

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Detailed Solution

It is given that the discriminant of quadratic equation

b^{2} - 4 ac = 0

.
The number of roots of a quadratic equation's solutions can be found using the discriminant, or formula under the radical that is

b^{2} - 4 ac

.
Given discriminant is,

b^{2} - 4 ac = 0

Let,

a x^{2} + bx + c = 0

be a standard quadratic equation then roots are

x = \frac{- b \pm \sqrt{b^{2} - 4 ac}}{2 a}

x = \frac{- b}{2 a}, \frac{- b}{2 a}

Hence, roots are real and equal.
Hence, the correct option is 1.

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