Q.

If the displacement of a particle moving with uniform acceleration along a straight line in the nthsecond is given by Sn =4+2n( in SI units), initial velocity of the particle is

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a

6ms1

b

7ms1

c

5ms1

d

4ms1

answer is B.

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Detailed Solution

sn =4+2n

sn =u+a(n12)

sn =u+ana2

=u+2ana2

 sn =4+2n

=4+2n22+22

=4+2n22+1

sn =5+2(n12)

sn =u+a(n12)

compare this equation

u=5ms1    a=2ms2

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