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If the displacement y of a particle is y = A sin (pt + qx), then

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the dimensions of pq are M°LT^–1

the dimensions of p/q are M°LT^–1

the dimensions of q are M°LT°

the dimensions of p are M°L°T

answer is C.

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Detailed Solution

Y = A sin (Pt + Qx)

Pt = 1, Qx = 1

P[T] = 1, Q[x] = 1

$P = \frac{1}{[T]} = [T^{- 1}], Q = \frac{1}{[L]} = [L^{- 1}] PQ = [T^{- 1}] [L^{- 1}] = [L^{- 1} T^{- 1}] \frac{P}{Q} = \frac{[T^{- 1}]}{[L^{- 1}]} = [{LT}^{- 1}]$

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