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If the displacement y of a particle is y = A sin(pt+qx), then the dimensions of 'p/q' is

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$M ° L ° T$

$M ° L T °$

$M ° L T^{- 1}$

$M ° L T^{- 2}$

answer is C.

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Detailed Solution

$P = T^{- 1} a n d q = L^{- 1}$
$∴ \frac{p}{q} = L T^{- 1}$

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