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If the distance between foci is 6 and minor axis is 8 then eccentricity of that ellipse is

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$\frac{1}{\sqrt{2}}$

$\frac{1}{\sqrt{5}}$

answer is A.

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Detailed Solution

$2 ae = 6, 2 b = 8 \Rightarrow b = 4, ae = 3$
but $b^{2} = a^{2} (1 - e^{2}) \Rightarrow 16 = a^{2} - 9 \Rightarrow a^{2} = 25$
$e = \sqrt{\frac{a^{2} - b^{2}}{a^{2}}} = \sqrt{\frac{25 - 16}{25}} = \frac{3}{5}$

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