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Q.

If the distance between the centres of the atoms of potassium and bromine in KBr molecule is 0.282 × 10^-9 m, the centre of mass of this two particle system from potassium is (mass of bromine = 80 u and of potassium = 39 u).

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a

9.3 × 10^-2 nm

b

18.96 × 10^-2 nm

c

27.9 × 10^-2 nm

d

3.3 × 10^-2 nm

answer is B.

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Detailed Solution

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Distance of CM from m₁ is

$\frac{m_{2} d}{m_{1} + m_{2}} = \frac{80 x 0.282 x 10^{- 9}}{39 + 80}$

= 0.1896 x 10^-9 m = 18.96 x 10^-2 nm

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If the distance between the centres of the atoms of potassium and bromine in KBr molecule is 0.282 × 10-9 m, the centre of mass of this two particle system from potassium is (mass of bromine = 80 u and of potassium = 39 u).