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If the distance between the top of two trees of height 20 m and 28 m is 17 m, then the horizontal distance between the trees is:

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15 m

14 m

16 cm

12 m

answer is B.

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Detailed Solution

Let AB and CD be two trees such that AB = 20 m, CD = 28 cm and BD = 17 cm.

Draw BE parallel to CD.

Then,

ED = CD − CE

⇒ ED = 28 − 20 [∵ AB = CE]

⇒ ED = 8 cm

In △BED, using Pythagoras Theorem,

BD² = BE² + ED²

⇒ (17)² = BE² + (8)²

⇒ BE²= 289 − 64 = 225

⇒ BE = 15 m

Therefore, AC = BE = 15 cm

Hence, the horizontal distance between the trees is 15 m.

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