If the distance of the object from the concave mirror is 4 times the focal length, where will the image position be?

$\text{u} = -4\text{f}$

Focal length of a concave mirror is negative (-f).

By mirror formula, we get

$\frac{1}{-\text{f}} = \frac{1}{-4\text{f}}+ \frac{1}{\text{v}}$

$\frac{1}{\text{v}} = \frac{1}{4\text{f}} - \frac{1}{\text{f}}$

$\frac{1}{\text{v}} = \frac{-3}{4\text{f}}$

$\text{v} = \frac{-4\text{f}}{3}$