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Q.

If the distance of the point $(a, 2)$ from the origin is $\sqrt{13}$ units, then the value of $a$ is

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a

0

b

$\pm 1$

c

$\pm 3$

d

$\pm 2$

answer is C.

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Detailed Solution

Given distance between two points $(0, 0), (a, 2) = \sqrt{13}$

$\sqrt{a^{2} + 4} = \sqrt{13}$

$a^{2} + 4 = 13$

$a^{2} = 9$

We get $a = \pm 3$

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