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Q.

If the distance travelled by a freely falling body in the last second of its journey is equal to the distance travelled in the first 2s, the time of descent of the body is

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a

1.5s

b

5s

c

2.5s

d

3s

answer is C.

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Detailed Solution

We know

Sn=12g(2n−1) & S2=12g22∴12g(2n−1)=12g×4;2n−1=4⇒2n=5⇒n=52=2.5

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