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If the E⁰cell for a given reaction has a negative value, which of the following gives the correct relationships for the values of $∆$ G⁰ and K_eq ?

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$∆$ G⁰ > 0and K_eq < 1

$∆$ G⁰ > 0and K_eq > 1

$∆$ G⁰ < 0and K_eq > 1

$∆$ G⁰ = 0 and K_eq = 0

answer is A.

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Detailed Solution

${ΔG}^{0} = - {nFE}^{0} and E_{cetl}^{0} = \frac{0.059}{n} \log K_{c}$

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