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Q.

If the electron falls from n = 3 to n = 2, in hydrogen atom then emitted energy is

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a

10.2 eV

b

12.09 eV

c

1.9 eV 

d

0.65 eV

answer is C.

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Detailed Solution

E1=13.6

E2=3.4

E3=1.51

E3E2=1.51+3.4=1.89eV

E3E2=1.9eV

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If the electron falls from n = 3 to n = 2, in hydrogen atom then emitted energy is