If the electron in an hydrogen atom jumps from an orbit with level n_f = 3 to an orbit with level n_f = 2, the emitted radiation has a wavelength given by

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$λ = \frac{36}{5 R}$

$λ = \frac{6}{R}$

$λ = \frac{5 R}{36}$

$λ = \frac{R}{6}$

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{1}{λ} = {Rz}^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}); \frac{1}{λ} = R (1)^{2} (\frac{1}{2^{2}} - \frac{1}{3^{2}}) \\ \frac{1}{λ} = R (\frac{5}{36}); λ = \frac{36}{5 R} \end{array}$

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