Q.

If the electronegativity difference between two atoms A and B is 2.0, the percentage of covalent character in the molecule is : 

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answer is 54.

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Detailed Solution

According to Hannay and Smith equation, 
% ionic character =16XAXB+3.5XAXB2
Where, XA and XB are the electronegativities of the atoms A and B respectively.
% ionic character =16(2)+3.5(2)2=32+14=46% % covalent character =10046=54%

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