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If the electronegativity of X be 3.2 and that of Y be 2.2, the percentage ionic character of XY is :

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19.5 (b) 18·.5
(c) 9.5 (d) 29.5

18·.5

9.5

29.5

answer is A.

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Detailed Solution

ENX - ENy = 3.2 - 2.2 = 1.
$∆$ = 1
[ $∆$ = difference of electronegativity values between x and y]
% ionic character= 16 ~ + 3.5 ~2 = 19.5

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