If the energy of the photon is increased by a factor of 4, then its momentum

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Does not change

Decreases by a factor of 4

Increases by a factor of 4

Decreases by a factor of 2

answer is C.

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Detailed Solution

$P = \frac{h}{λ}, E = \frac{hc}{λ} \Rightarrow E = Pc .$

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