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Q.

If the enthalpy change for the transition of liquid water to steam is 30 kJ mol−1 at 27∘C, the entropy change for the process would be

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a

10 J mol−1K−1

b

0.1 J mol−1K−1

c

1.0 J mol−1K−1

d

100 J mol−1K−1

answer is D.

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Detailed Solution

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 We know that ΔG=ΔH−TΔS        ΔH=TΔS [∵ΔG=0]

ΔS=ΔHT=30×103300=100Jmol−1K−1

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