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Q.

If the equation ax2+bx+c=0,cx2+bx+a=0,ac  have a negative common root, then the value of ab+c is

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a

answer is `.

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Detailed Solution

ax2+bx+c=0&cx2+bx+c=0 have a negative common root then

(c2a2)2=(abbc)(abbc)

(c+a)2(ca)2=b2(ac)2

(c+a)2b2=0

(c+a+b)(a+cb)=0

ab+c=0  

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