If the equation of motion of a projectile is y=3x−18x2, The range and maximum height are respectively (y and x are in metres)

When y=0 x=R3x=18x2x=24 m R=24 m when x=R2 y=Hy=H=312-18122H=18 m

If the equation of motion of a projectile is y=3x−18x2, The range and maximum height are respectively (y and x are in metres)

When y=0 x=R3x=18x2x=24 m R=24 m when x=R2 y=Hy=H=312-18122H=18 m

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If the equation of motion of a projectile is $y = 3 x - \frac{1}{8} x^{2}$ , The range and maximum height are respectively (y and x are in metres)

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Detailed Solution

When y=0 x=R

$3 x = \frac{1}{8} x^{2}$

$x = 24 m$

$R = 24 m$

$when x = \frac{R}{2} y = H$

$y = H = 3 (12) - \frac{1}{8} {(12)}^{2}$

$H = 18 m$

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If the equation of motion of a projectile is y=3x−18x2, The range and maximum height are respectively (y and x are in metres)

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If the equation of motion of a projectile is $y = 3 x - \frac{1}{8} x^{2}$ , The range and maximum height are respectively (y and x are in metres)