Q.

If the equation x+y+z=6;  x+2y+3z=10,  2x+4y+λz=24 has no solution and product of roots of f(y)=|2y2c1λ|=0 is 12 then value of c = …..

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answer is 144.

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Detailed Solution

|24λ111123|=0λ=6

f(y)=|2y2c1λ|=0λ2y2+c=0s2=c(2λ)=12

c=144

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