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Q.

If the equation x2+2k+2x+9k=0 has equal roots then k = ?


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a

1 or 4

b

-1 or -4 

c

1 or -4

d

-1 or 4

answer is A.

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Detailed Solution

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Given quadratic equation is,
x2+2k+2x+9k=0.
We know that a quadratic equation ax2+bx+c=0 has two equal roots if b2-4ac=0.
After comparing the given equation x2+2k+2x+9k=0 with the standard form of the quadratic equation, we get,
a=1,b=2(k+2),c=9k.
Then,
b2-4ac=0
2k+22-4×1×9k=0
2k+42-36k=0
4k2+16k+16-36k=0
4k2-36k+16k+16=0
4k2-20k+16=0
4k2-16k-4k+16=0
4kk-16-4k-4=0
4k-4k-4=0
4k-4=0 or k-4=0
4k-1=0 or k=4
k-1=0 or k=4
 k=1  or k=4
If the equation x2+2k+2x+9k=0 has equal roots then k = 1 or 4.
Hence, the correct option is 1.
 
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