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Q.

If the equation cos4θ+sin4θ+λ=0 has a real solution for θ, then λ lies in the interval

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a

(-1/2, -1/4]

b

(-5/4, -1]

c

[-1, -1/2]

d

[-3/2, -5/4]

answer is B.

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Detailed Solution

sin4θ+cos4θ+λ=0λ=sin4θ+cos4θ=sin2θ+cos2θ22sin2θcos2θ=1sin22θ2λ=1+12sin22θ1,12

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