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Q.

If the equation k(6x2+3)+rx+2x21=0 and 6k(2x2+1)+px+4x22=0 have both the roots common then the value of 2r-p is '

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a

2

b

1

c

0

d

3

answer is A.

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Detailed Solution

Givenk(6x2+3)+rx+(2x21)=0(1)and  6k(2x2+1)+px+(4x22)=03k(2x2+1)+p2x+(2x21)=0(2)comparing(1)&(2)r=p22rp=0

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If the equation k(6x2+3)+rx+2x2−1=0 and  6k(2x2+1)+px+4x2−2=0 have both the roots common then the value of 2r-p is '