If the equations 2x2 + kx - 5 = 0 and x2 - 3x - 4 = 0 have a common root, then the value of k is

(x – 4)(x + 1) = 0 substitute x = –1 ⇒2 - K - 5 = 0 ⇒ K = -3substitute x = 4 ⇒ 32 + K4 - 5 ⇒ K = -27/4

If the equations 2x2 + kx - 5 = 0 and x2 - 3x - 4 = 0 have a common root, then the value of k is

(x – 4)(x + 1) = 0 substitute x = –1 ⇒2 - K - 5 = 0 ⇒ K = -3substitute x = 4 ⇒ 32 + K4 - 5 ⇒ K = -27/4

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If the equations 2x² + kx - 5 = 0 and x² - 3x - 4 = 0 have a common root, then the value of k is

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-2

-3

27/4

-1/4

answer is B.

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Detailed Solution

(x – 4)(x + 1) = 0

substitute x = –1 $\Rightarrow$ 2 - K - 5 = 0 $\Rightarrow$ K = -3
substitute x = 4 $\Rightarrow$ 32 + K4 - 5 $\Rightarrow$ K = -27/4

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If the equations 2x2 + kx - 5 = 0 and x2 - 3x - 4 = 0 have a common root, then the value of k is

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If the equations 2x² + kx - 5 = 0 and x² - 3x - 4 = 0 have a common root, then the value of k is