Q.

If the equations  4x211x+2k=0 and x23xk=0 have a common root and obtain the common root for this value of 'k' is

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a

736

b

367

c

1736

d

1736

answer is C.

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Detailed Solution

Let (xα)  is common root for 4x211x+2k=0(1)

x23xk=0(2)

From (1) and (2),

4α211α+2k=0 and α23αk=0

4α2=11α2k

α2=11α2k4(3)

α2=3α+k(4)

11α2k4=3α+k1

11α2k=4(3α+k)11α2k=12α+4k

2k4k=12α11α

6k=α sub equation (4)

(6k)2=3(6k)+k

36k2=18k+k36k2=17k

k=1736 sub in above equation α=0,176.

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