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Q.

If the equations x2xp=0  and  x2+2px12=0  have a common root then that root is           

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a

2

b

1

c

Cannot be determined

d

p+2

answer is C.

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Detailed Solution

(c1a2c2a1)2=(b1c2b2c1)(a1b2a2b1)

(p+12)2=(12+2p2)(2p+1)

4p3+p2+48p132=0

p=2, the common root is 2

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