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If the error in the measurement of the radius of a sphere is 1% then the error in the measurement of its volume is

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$9 %$

$1 %$

$3 %$

$\frac{1}{3} %$

answer is C.

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Detailed Solution

Volume= $\frac{4 π R^{3}}{3}$

$\frac{Δ V}{V} \times 100 = 3 \frac{Δ R}{R} \times 100$

$= 3 \times \frac{1}{100} \times 100$

$= 3 %$

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