If the first two terms of a H.P are $\frac{1}{16}$ and $\frac{1}{13}$, find the maximum partial sum

The terms of the H.P are $\frac{1}{16},\frac{1}{13},\frac{1}{10},\frac{1}{7},\frac{1}{4},\frac{1}{1},\frac{1}{-2},\frac{1}{-5}$

So the maximum partial sum is $\frac{1}{16}+\frac{1}{13}+\frac{1}{10}+\frac{1}{7}+\frac{1}{4}+\frac{1}{1}$

$=0.0625+0.0769+0.1+0.1428+0.25+1=1.63$