Q.

If the focus is (1,1) and the directrix is the line x+2y9=0 , the vertex of the parabola is 

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a

(2,1)

b

(1,2)

c

(1,2)

d

(2,1)

answer is B.

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Detailed Solution

Question Image

Foot of perpendicular from a point (x1,y1) to the straight directrix 

hx1a=ky1b=(ax1+by1+c)a2+b2

h11=k+12=(129)5

h=3,  k=3

Z(h,k)=(3,3)

Vertex is midpoint of ZS¯

A=(3+12,312)=(2,1)

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