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If the formation of diatomic boron molecule is predicted based on MO theory, the bond order would be

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12.0

1.0

0.5

1.5

answer is B.

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Detailed Solution

B2 = [5 + 5 = 10e^-] ⇒

M.O.E.order :

\large \sigma 1{s^2}\,{\sigma ^*}1{s^2}\;\sigma 2{s^2}\;{\sigma ^*}2{s^2}\;\begin{array}{*{20}{c}} {\pi 2{p_x}^1} \\ {\pi 2{p_y}^1} \end{array}\;\sigma 2pz\;\begin{array}{*{20}{c}} {{\pi ^*}2{p_x}} \\ {{\pi ^*}2{p_y}} \end{array}{\sigma ^*}2{p_z}\

\large B.O = \frac{N_b - N_a}{2} = \frac{6 - 4}{2} = \frac{2}{2} = 1

No of electrons	8	9	10	11	12	13	14	15	16	17	18	19	20
B.O	0	0.5	1.0	1.5	2.0	2.5	3.0	2.5	2.0	1.5	1.0	0.5	0

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