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If the formation of diatomic boron molecule is predicted based on MO theory, the bond order would be

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0.5

1.0

1.5

12.0

answer is B.

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Detailed Solution

B2 = [5 + 5 = 10e^-] ⇒

M.O.E.order :

large sigma 1{s^2},{sigma ^*}1{s^2};sigma 2{s^2};{sigma ^*}2{s^2};begin{array}{*{20}{c}} {pi 2{p_x}^1} \ {pi 2{p_y}^1} end{array};sigma 2pz;begin{array}{*{20}{c}} {{pi ^*}2{p_x}} \ {{pi ^*}2{p_y}} end{array}{sigma ^*}2{p_z}

large B.O = frac{N_b - N_a}{2} = frac{6 - 4}{2} = frac{2}{2} = 1

No of electrons	8	9	10	11	12	13	14	15	16	17	18	19	20
B.O	0	0.5	1.0	1.5	2.0	2.5	3.0	2.5	2.0	1.5	1.0	0.5	0

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