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Q.

If the formation of diatomic boron molecule is predicted based on MO theory, the bond order would be

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a

0.5

b

1.0

c

1.5

d

12.0

answer is B.

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Detailed Solution

B2 = [5 + 5 = 10e-] ⇒

M.O.E.order :

large sigma 1{s^2},{sigma ^*}1{s^2};sigma 2{s^2};{sigma ^*}2{s^2};begin{array}{*{20}{c}} {pi 2{p_x}^1} \ {pi 2{p_y}^1} end{array};sigma 2pz;begin{array}{*{20}{c}} {{pi ^*}2{p_x}} \ {{pi ^*}2{p_y}} end{array}{sigma ^*}2{p_z}
large B.O = frac{N_b - N_a}{2} = frac{6 - 4}{2} = frac{2}{2} = 1
No of electrons891011121314151617181920
B.O00.51.01.52.02.53.02.52.01.51.00.50

 

 

 

 

 

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