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If the fourth term in the binomial expansion of ${(\frac{2}{x} + x^{\log_{8}^{x}})}^{6}$ (x>0) is 20 x 8⁷, then a value of x is.

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8^-2

8³

8²

answer is B.

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Detailed Solution

$T_{4} = 6_{C} {(\frac{2}{x})}^{3} {(x^{\log_{8}^{x}})}^{3} = 20 \times 8^{7}$

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