If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex (which behaves as a strong electrolyte) is $- 0.0558 ° C,$ the number of chloride (s) in the coordination sphere of the complex is: $[K_{f} f o r w a t e r = 1.86 K k g m o l^{- 1}]$

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Detailed Solution

$Δ T_{f} = i K_{f} \times m 0.0558 = i \times 1.86 \times 0.01, i = 3 .$

Thus, the complex should give three ions in the aqueous solution. Molecular formula of the complex will be : $[C o {(N H_{3})}_{5} C l] C l_{2} .$

$∴$ Only one chloride ion will be with in the coordination sphere.]

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