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Q.

If the frequency of a incident light is 6×1014 Hz, then what will be the wavelength of this light and lies in which region.

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a

600 nm, Infrared region

b

600 nm, Visible region

c

500 nm, Infrared region

d

500 nm, Visible region

answer is A.

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Detailed Solution

Wavelength, λ=cν

=3×1086×1014=0.5×10-6=500 nm

This wavelength lies in the visible region.

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