If the function f(x) = asin(x) + 13sin(3x) attains maximum value at x=π3 then ‘a’ equals

fx=asinx+13sin3x ⇒fIx=acosx+13cos3x3 =acosx+cos3xGiven fx is maximum at x=π/3⇒fIπ/3=0 ⇒a1/2+-1=0 ⇒a/2=1⇒a=2

If the function f(x) = asin(x) + 13sin(3x) attains maximum value at x=π3 then ‘a’ equals

fx=asinx+13sin3x ⇒fIx=acosx+13cos3x3 =acosx+cos3xGiven fx is maximum at x=π/3⇒fIπ/3=0 ⇒a1/2+-1=0 ⇒a/2=1⇒a=2

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If the function $f (x) = a \sin (x) + \frac{1}{3} \sin (3 x)$ attains maximum value at $x = \frac{π}{3}$ then ‘a’ equals

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$\begin{array}{rcl} f (x) & = & asinx + \frac{1}{3} \sin 3 x \\ \Rightarrow & f^{I} (x) = acosx + \frac{1}{3} (\cos 3 x) 3 \\ = & acosx + \cos 3 x \end{array}$

Given $f (x)$ is maximum at $x = π / 3$

$\Rightarrow f^{I} (π / 3) = 0 \Rightarrow a (1 / 2) + (- 1) = 0 \Rightarrow a / 2 = 1 \Rightarrow a = 2$

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If the function f(x) = asin(x) + 13sin(3x) attains maximum value at x=π3 then ‘a’ equals

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If the function $f (x) = a \sin (x) + \frac{1}{3} \sin (3 x)$ attains maximum value at $x = \frac{π}{3}$ then ‘a’ equals