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Q.

If the HCF of numbers 408 and 1032 can be expressed in the form of 1032x-408×5, then find the value of x.


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a

0

b

1

c

2

d

3  

answer is C.

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Detailed Solution

Given numbers are 408 and 1032.
The HCF is in the form of 1032x-408×5.
We need to find the value of x.
408=2×2×2×3×17 1032=2×2×2×3×43 So,
HCF=2×2×2×3
HCF=24 Now, comparing the Euclid’s division algorithm i.e., a=bq+r with 1032x-408×5,
Here, a=24, b=1032,
1032x-408×5=24 1032x=2064
x=2
Therefore, the value of x=2.
Hence, option 3 is correct.
 
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