If the heat of neutralization for a strong acid-base reaction is -57.1kJ,what would be the heat released in $- k j m o l^{- 1}$ when $350 c m^{3}$ of $0.20$ M of a dibasic strong acid is mixed with 650 $c m^{3}$ of 0.10 M monoacidic base?

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Detailed Solution

Mill moles of dibasic strong acid
$\begin{array}{l} = M \times V = 0.20 \times 350 = 70 m m o l \\ ∴ A m o u n t o f H^{+} i o n s i n t h e a c i d \\ = 2 \times 70 = 140 m m o l \end{array}$
Similarly, amount of ions in monobasic strong base
$\begin{array}{l} = 0.10 \times 650 \times 1 = 65 m m o l \\ [H e r e, O H^{-} i s t h e \lim i t i n g r e a c \tan t] . \\ ∴ 1 m o l e o f O H^{-} i o n s p r o d u c e s \\ = 57.1 k J h e a t 65 \times 10^{- 3} m o l e s o f O H^{-} \\ i o n s w i l l p o r o d u c e \\ = 57.1 \times 65 \times 10^{- 3} = 3.71 k J \end{array}$