If the incentre of an equilateral triangle is (1, 1) and the equation of its one side is $3x+4y+3=0$ then the equation of the circumcircle of this triangle is

In an equilateral triangle, incentre and circumcenter are same and  $R=2r$

Now, $r=\frac{|3+4+3|}{\sqrt{9+16}}=2$ 

$\Rightarrow R=4$

$\therefore$ Equation of circumcircle is $(x-1{)}^2+(y-1{)}^2=16$

$\Rightarrow x^2+y^2-2x-2y-14=0$