If the ionic product of water is $1.96 \times 10^{- 14}$ at 35⁰C, its value at 10⁰C is

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[ $2.95 \times 10^{- 15}$ ]

[ $1.96 \times 10^{- 13}$ ]

[ $1.96 \times 10^{- 14}$ ]

[ $3.92 \times 10^{- 14}$ ]

answer is C.

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Detailed Solution

The temperature and the ionic product have a direct relationship, meaning that the ionic product is directly proportional to temperature. The ionic product also diminishes as the temperature drops.

According to the theory, water's ionic product similarly drops when the temperature (10⁰C) decreases.

It is clear from the options given that the only value less than the current number is [ $2.95 \times 10^{- 15}$ ].

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