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If the ionisation enthalpy and electron gain enthalpy of an element are 275 and 86k.cal/mole respectively, then the electronegativity of the element on the pauling scale is

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2.1

2.8

4.0

2.6

answer is B.

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Detailed Solution

I.E + E.A = 275+86 = 361k.cal/mole
= 361x4.184=1510.42kJ/mol
E.N= $\frac{1510.42}{540} = 2.79 \approx 2.8$

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