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If the Ionisation potential (I.P.) of Na is 5.48 eV. The I.P. of K will be

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5.68 eV

10.88 eV

5.48 eV

4.34 eV

answer is A.

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Detailed Solution

If the Ionisation potential (I.P.) of Na is 5.48 eV. The I.P. of K will be 4.34 eV.

Since, K lies below Na and I.P decreases down the group.

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