If the ionization enthalpy and electron gain enthalpy of an element are 275 and 86 kcal ${mol}^{- 1}$ respectively, then the electronegativity of the element on the Pauling scale is:
(Round off to nearest Integer)

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answer is 3.

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Detailed Solution

$\begin{array}{l} |X_{A} - X_{B}| = 0 \cdot 102 \times \sqrt{ΔE} = 0 \cdot 102 \times \sqrt{{(275 - 86) \times 4 \cdot 18} kJ / mol} \\ = 0 \cdot 102 \times 28 \cdot 1069 \\ = 2 \cdot 86 \approx 3 \end{array}$

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