If the kinetic energy of a body increases by 125%, the percentage increase in its momentum is,

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If the kinetic energy of a body increases by 125%, the percentage increase in its momentum is,

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62.5%

250%

50%

200%

answer is A.

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Detailed Solution

$KE \propto p^{2} \Rightarrow \frac{P_{2}}{P_{1}} = \sqrt{\frac{{KE}_{2}}{{KE}_{1}}}$

$\Rightarrow (\frac{P_{2}}{P_{1}} - 1) \times 100 = (\frac{15}{10} - 1) \times 100 = 50 %$

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