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Q.

If the kinetic energy of the moving particle is E, then the de-Broglie wavelength is

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a

$λ = \sqrt{(\frac{2 mE}{h})}$

b

$λ = \frac{h}{\sqrt{2 mE}}$

c

$λ = h \sqrt{2 mE}$

d

$λ = \frac{hE}{\sqrt{2 mE}}$

answer is C.

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Detailed Solution

$λ = \frac{h}{mv} E = \frac{1}{2} {mv}^{2} or 2 mE = m^{2} v^{2} or mv = \sqrt{2 mE} λ = \frac{h}{\sqrt{2 mE}}$

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